-25x^2+158x-36=0

Solution for -25x^2+158x-36=0 equation:

-25x^2+158x-36=0

a = -25; b = 158; c = -36;
Δ = b2-4ac
Δ = 1582-4·(-25)·(-36)
Δ = 21364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21364}=\sqrt{196*109}=\sqrt{196}*\sqrt{109}=14\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(158)-14\sqrt{109}}{2*-25}=\frac{-158-14\sqrt{109}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(158)+14\sqrt{109}}{2*-25}=\frac{-158+14\sqrt{109}}{-50}
$